2-0.5x=4-0.25x^2

Solution for 2-0.5x=4-0.25x^2 equation:

2-0.5x=4-0.25x^2

We move all terms to the left:

2-0.5x-(4-0.25x^2)=0

We get rid of parentheses

0.25x^2-0.5x-4+2=0

We add all the numbers together, and all the variables

0.25x^2-0.5x-2=0

a = 0.25; b = -0.5; c = -2;
Δ = b2-4ac
Δ = -0.52-4·0.25·(-2)
Δ = 2.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{2.25}}{2*0.25}=\frac{0.5-\sqrt{2.25}}{0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{2.25}}{2*0.25}=\frac{0.5+\sqrt{2.25}}{0.5}
$